Matemática, perguntado por samuelpmatosp1d60c, 9 meses atrás

Fatore: (√ 2 + x /√2)^ 3

Soluções para a tarefa

Respondido por pthime
1

Resposta: 2\sqrt{2} + 3\sqrt{2} *x + \frac{3\sqrt{2}*x^{2}  }{2} + \frac{\sqrt{2}*x^{3}  }{4}

Explicação passo-a-passo:

((\sqrt{2} + \frac{x}{\sqrt{2} })^{2})*(\sqrt{2} + \frac{x}{\sqrt{2} }) <=>\\<=> ((\sqrt{2} )^{2} + 2*\sqrt{2} * \frac{x}{\sqrt{2} } + (\frac{x}{\sqrt{2} })^{2}) * (\sqrt{2} + \frac{x}{\sqrt{2} }) <=>    \\<=> (2 + 2*x+ \frac{x^{2} }{2} ) * (\sqrt{2} + \frac{x}{\sqrt{2} }) <=>\\\\<=> 2\sqrt{2} + \frac{2*x}{\sqrt{2} } + 2\sqrt{2}*{x} + \frac{2*x^{2} }{\sqrt{2} } + \frac{\sqrt{2} *x^{2} }{2}   + \frac{x^{3} }{2\sqrt{2} } <=>\\

<=> 2\sqrt{2} +\frac{2\sqrt{2}*x }{2} + 2\sqrt{2} *x + \frac{2\sqrt{2}*x^{2}  }{2} + \frac{\sqrt{2}*x^{2}  }{2} + \frac{x^{3}*\sqrt{2}  }{4} <=>\\<=> 2\sqrt{2} + 3\sqrt{2} *x + \frac{3\sqrt{2}*x^{2}  }{2} + \frac{\sqrt{2}*x^{3}  }{4}

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