Question

fatoração:
$a) \frac{n-5}{5-n} b) \frac{27x^3+9x^2}{3+9x} c) \frac{x^4-y^4}{x^2-y^2}$

Answer 1

Oiiii

$\boxed{a) \frac{n-5}{5-n} = - \frac{-n+5}{5-n} = -\frac{5-n}{5-n} =\boxed{ -1}}$

$\boxed{b) \frac{27x^3+9x^2}{3+9x}= \frac{9 x^{2} (3x+1)}{3+9x}= \frac{9 x^{2} (3x+1)}{3(1+3x)}= corta=\frac{9 x^{2} }{3} =\boxed{3 x^{2} }}$

$\boxed{ c) \frac{x^4-y^4}{x^2-y^2} = \frac{(x^2)^2-(y^2) ^{2} }{x^2-y^2} = \frac{(x^2-y^{2})(x^2+y^2) }{ (x^{2} -y^2)} = \boxed{ x^2+y^2}}$