Question

façam ae vlw qm poder ajudar


2x+y²=4
3x-y=2

thx

Answer 1

$\boxed{ \left \{ {{2x+y^2=4} \atop {3x-y=2}} \right. }$

$3x-y=2\\-y=2-3x~(-1)\\y=-2+3x$

$2x+(-2+3x)^2=4\\2x+(4-12x+9x^2)=4\\9x^2-10x=0\\x(9x-10)=0\\x'=0\\x''= \frac{10}{9}$

$\boxed{x= \frac{10}{9} }$

Usando o x''

$y=-2+3x\\y=-2+ \frac{3.10}{9}$

$\boxed{y= \frac{4}{3} }$

Answer 2

Equação I  2x+y²=4
Equação II  3x-y=2  isolando o y    -y=2 -3x (-1)      y = 3x-2
Substituindo na I
2x + ( 3x -2)²=4
2x + 9x² - 12x + 4 =4
9x² -10x =0
x'=0
x"= 10/9 

y = 3x-2
y= 3.10/9 -2
y=4/3