Question

Faça as seguintes transformações.a- 30 °C p/°Fb-100 °F / °Cc- 0 °F p/ °Cd- -30 °C p/ °F

Answer 1

a)
30°C→°F
(30-0/100-0)=(x-32/212-32)
30/100=(x-32)/180
100x-3200=5400
100x=2200
x=22°F

b)
100°F→°C
(x-0)/(100-0)=(100-32)/(212-32)
x/100=68/180
180x=6800
x=37,7°C

c)
0°F→°C
(0-32)/(211-32)=(x-0)/(100-0)
-32/180=x/100
180x= -3200
x= -17,7°C

d)
-30°C→°F
(-30-0)/(100-0)=(x-32)/(212-32)
-30/100=(x-32)/180
100x-3200= -5400
100x= -2200
x= -22°F