Question

faça a convenção das escalas abaixo?
a) 10ºc em f°?
b)68ºf em °c?

Answer 1

a)

$\frac{Tc}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$\frac{10}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$2 \ = \ \frac{Tf \ - \ 32}{9}$

$18 \ = \ Tf \ - \ 32$

$\boxed{ T_{F} \ = \ 5 0^{ \ 0} F }$

b)

$\frac{Tc}{5} \ = \ \frac{Tf \ - \ 32}{9}$

$\frac{Tc}{5} \ = \ \frac{68 \ - \ 32}{9}$

$\frac{Tc}{5} \ = \ \frac{36}{9}$

$9 \ Tc \ = \ 180$

$Tc \ = \ \frac{180}{9}$

$\boxed{Tc \ = \ 2 0^{0}C }$