Question

f(x)=x2-6x+9

f(x)=-x2+7x-10

Answer 1

A)

F(x) = x^2-6x+9
0 = x^2 - 6x + 9
a= 1; b = - 6; c = 9
∆ = b^2-4ac
∆ = (-6)^2 - 4.1.9
∆ = 36 - 36
∆ = 0

x = [ - b +/- √∆]/2a
x = [ -(-6) +/- √0]/2.1
x = 6/2
x = 3

B)

f(x)= - x^2+7x-10
0 = - x^2 + 7x - 10 (-1)
0 = x^2 - 7x + 10
a= 1; b = - 7; c = 10
∆ = b^2-4ac
∆ = (-7)^2 - 4.1.10
∆ = 49 - 40
∆ =9
x = [ - b +/- √∆]/2a
x = [ - (-7) +/- √9]/2.1
x = [7 +/- 3]/2

x' = [7+3]/2 = 10/2 = 5
x" = [7 - 3]/2 = 4/2 = 2