Question

f(x) = -x2 +4
vértice da parábola e zeros da função

Answer 1

Resposta:

1+1=

Explicação passo a passo:

Answer 2

Coordenadas do vértice da parábola:

$\mathsf{V\left(-\dfrac{b}{2a},\ -\dfrac{\Delta}{4a}\right)}$

$\mathsf{x_v = -\dfrac{b}{2a}=-\dfrac{0}{2\cdot(-1)}=0}$

$\mathsf{y_v=-\dfrac{\Delta}{4a}=-\dfrac{0^2-4\cdot(-1)\cdot4}{4\cdot(-1)}=-\dfrac{0+16}{-4}=-\left(-\dfrac{16}{4}\right)=4}$

Zeros da função:

$\mathsf{-x^2+4=0}\\\\\mathsf{-x^2=-4}\\\\\mathsf{x^2=4}\\\\\mathsf{x=\pm\sqrt4}\\\\\mathsf{x=\pm2}$