Question

F(x)=6x^2-4x+3 definida no ponto x = 4

Answer 1

$f(x)=6x^2-4x+3\\\\\frac{dy}{dx}=6.2x-4\\\\\frac{dy}{dx}=12x-4\\\\f'(4)=12.4-4\\f'(4)=48-4\\f'(4)=44$

Answer 2

f(x)=6x^2 - 4x + 3
f'(x)= 12x - 4