Question

f(x)=2x-4e g(x)=3x+a se f(1)-g(0)=6,quanto vale f(2)+5g(7)?

Answer 1

f(x)=2x-4

f(1) = 2*1 - 4 = 2 - 4 = -2

f(1) = -2

g(x)=3x+a

g(0) = 3*0 + a

g(0) = a

Como f(1)-g(0)=6 ---> -2 -a = 6 ----> a = -8

Logo:

g(x) = 3x - 8

f(x) = 2x-4

f(2) = 2*2 - 4 = 4-4 = 0

f(2) = 0

g(7) = 3*7 - 8 = 21 - 8 = 13

g(7) = 13

Portanto:

f(2)+5g(7) = 0 + 5*13 = 65

f(2)+5g(7) = 65