Question

f) {[(8×4+3)÷7+(3+15÷5)×3]×2-(19-7)÷6}×2+12​

Answer 1

Resposta:

$\sf \{[(8 \times 4+3)\div 7+(3+15\div 5)\times 3]\times 2- (19 - 7) \div 6\} \times 2 + 12 =$

$\sf \{[(32+3)\div 7+(3+3)\times 3]\times 2-12 \div 6\} \times 2 + 12 =$

$\sf \{[35\div 7+ 6 \times 3]\times 2-2\} \times 2 + 12 =$

$\sf \{[8 + 6 \times 3]\times 2-2\} \times 2 + 12 =$

$\sf \{[8 + 18]\times 2-2\} \times 2 + 12 =$

$\sf \{26\times 2-2\} \times 2 + 12 =$

$\sf \{52-2\} \times 2 + 12 =$

$\sf 50\times 2 + 12 =$

$\sf 100 + 12 =$

$\boldsymbol{ \sf \displaystyle 112}$

Explicação passo-a-passo: