Question

f) 3x + 2 [x+(x+(11).3]=88

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Answer 1

3x + 2 [x+(x+(11).3]=88
3x + 2[x + (x + 33)] = 88
3x + 2[x + x + 33] = 88
3x + 2[2x + 33] = 88
3x + 4x + 66 = 88
7x + 66 = 88
7x = 88 - 66
7x = 22
x = 22/7

Answer 2

   3x + 2 [x+(x+(11).3]=88
   

 3x + 2 [x+x+33]=88 
  3x + 2 [2x+33]=88 
    3x + 4x + 66 = 88
           7x = 88 - 66
            7x = 11
              x = 11
                     7