f(3) =1
f(a.b) = f(a) + f(b) Calcule:
d) f(1/3)
f) f(√3)
Soluções para a tarefa
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Ola Refundini
f(a*b) = f(a) + f(b)
logx(a*b) = logx(a) + logx(b)
logx(3) = 1 , log3(3) = 1 , x = 3
f(x) = log3(x)
f(1(3) = log3(1/3) = -log3(3) = -1
f(√3) = log3(3)/2 = 1/2
f(a*b) = f(a) + f(b)
logx(a*b) = logx(a) + logx(b)
logx(3) = 1 , log3(3) = 1 , x = 3
f(x) = log3(x)
f(1(3) = log3(1/3) = -log3(3) = -1
f(√3) = log3(3)/2 = 1/2
Refundini:
Obrigado ! Sabe resolver de outra forma sem usar Logs?
Preciso fazer sem os logs hehe
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