Question

f) 23 x 3 – √(6 x 8 + 1) =





ALGUEM ME AJUDAAAAA
g) [16 ÷ 8 + (4 ÷ 2 + 2 x 1)2 ] – 5 =

h) (23 x 32 – 62) ÷ [18 ÷ (15 – 3 x 22)]2 =

i) 2 x [(6 + 7 x √9) ÷ 32 + (21 – 5 x √4)] =

j) [√100 + (24 – 8) x 2 + 24] ÷ [22 - (1 + 2)] =

Answer 1

Resposta:Segue as contas abaixo na explicação

Explicação passo-a-passo:

f)23 x 3 – √(6 x 8 + 1) =

 69-√(48+1)

 69-√49

 69-7

 62

g) [16 ÷ 8 + (4 ÷ 2 + 2 x 1)^2 ] – 5 =

   [2+(2+2)^2]-5

   [2+4^2]-5

   [2+8]-5

    10-5

      5

h) (23 x 32 – 62) ÷ [18 ÷ (15 – 3 x 22)]2

    (736-62)÷[18÷(15-66)]^2

     674÷[18÷(-51)]^2

     674÷[324÷2601]

     674÷842724:2/2

     337÷421362

i) 2 x [(6 + 7 x √9) ÷ 32 + (21 – 5 x √4)]

  2 x [(6+7 x 9)÷(21-5 x 2)]

  2 x [(6+63)÷(21-10)]

  2 x [69÷11]

  138÷22 :2/2

  69÷11