Question

.f(0) = 2
. f(1) = 3
. f(n+1) = 2f(n) - f(n-1)
e calcular o valor de f(5)

Answer 1

f(n+1)=2*f(n)-f(n-1)
n=0
f(1)=2*f(0)-f(-1)
3=2*2-f(-1)
-f(-1)=3-4
f(-1)=1

logo
f(x)=x+2
então
f(5)=5+2=7

prova:
f(3)=3+2=5
f(4)=4+2=6

n=4
f(5)=2*f(4)-f(3)
f(5)=2*6-5
f(5)=7