Question

Extração da raiza quadrada dos quadrados perfeitos usando a divisão dos expoemtes
252
441
625
729
784
1200
2000
3025
10000

Answer 1

Olá!

252 Penso que quis escrever 256
=> V256 = V16^2 = (16^2)^1/2 = 16^2/2=16^1=16

441
=> V441
=> V21^2
=> (21^2)^1/2
=> 21^2/2
=> 21

625
=> V625
=> V25^2
=> (25^2)^1/2
=> 25^2/2
=> 25

729
=> V729
=> V27^2
=> (27^2)^ 1/2
=> 27^2/2
=> 27

784
=> V784
=> V28^2
=> (28^2)^1/2
=> 28^2/2
=> 28

1225
=> V1225
=> V35^2
=> (35^2)^1/2
=> 35^2/2
=> 35

2025
=> V2025
=> V45^2
=> (45^2)^1/2
=> 45^2/2
=> 45

3025
=> V3025
=> V55^2
=> (55^2)^1/2
=> 55^2/2
=> 55

10000
=> V10000
=> V100^2
=> (100^2)^1/2
=> 100^2/2
=> 100

Espero ter ajudado!

Answer 2

252: 2
126: 2
63: 3
21: 3
7: 7
----------
1  =  2².3².7 = √2².√3².7 = 2.3√7 = 6√7

**********************************************
441: 21
21: 21
------------------
1  =   21²  =  √21² = 21

√441 = 21

**********************************

625 : 5
125: 5
25: 5
5: 5
------------
1   = 5.5.5.5 = 5².5² = √5².√5² = 5.5 = 25

******************************************
729: 3
243: 3
81: 3
27: 3
9: 3
3: 3
--------------
1  = 3.3.3.3.3.3 = 3².3².3² = √9.√9.√9 =  3.3.3 = 27

****************************************
784: 2
392: 2
196: 2
98: 2
49: 7
7: 7
-------------
1  = 2.2.2.2.7.7 = 16.49 = √16.√49 = 4.7 = 28

*****************************************
1200: 2
600: 2
300: 2
150: 2
75: 3
25: 5
5: 5
--------------
1  = 2.2.2.2.3.5.5 = 16.3.25 = √16.√3.√25 = 4.√3.5 = 4.5√3 = 20√3

***************************************************
2000 : 2
1000 : 2
500 : 2
250: 2
125: 5
25: 5
5: 5
----------------
1   = 2.2.2.2.5.5.5 = √16.√25.√5 = 4.5√5 = 20√5

***************************
3025: 5
605: 5
121: 11
11: 11
--------------
1 = 5².11² = √5².√11² = 5.11 = 55

*********************************
10000: 2
5000: 2
2500: 2
1250: 2
625: 5
125: 5
25: 5
5: 5
*******************
1       =  2.2.2.2.5.5.5.5 = √16.√5².√5² = 4.5.5 = 100

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