Question

Exercio 3 da imagem, resultado e)5/6 mas preciso da resolucão

Answer 1

Oi.

$\\ \\ \\ (x - y) = \sqrt[3]{3} = 3^{1/3} \\ \\ log _{3} (x - y) = 1/3 \\ \\ (x + y) = \sqrt{3} = 3 ^{1/2} \\ \\ log _{3} (x + y) = 1/2 \\ \\ log _{3}(x^2 - y^2) = log _{3} (x + y) . (x - y) = log_{3} (x + y) + log _{3} (x - y) \\ \\ log _{3}(x^2 - y^2) = 1/2 + 1/3 = 5/6$

Bons estudos!