Question

exercícios sobre potências

1)calcule o valor de:

A)7²=

B)9⁰=

C)-10⁶

D)(-10)⁶

E)(-3)²

F)(-3)³

G)(-3)⁴

h) (-0,3)⁴

i)
$( - \frac{3}{2} ) {}^{2} =$
J)
$( - \frac{3}{4} ) {}^{3} =$
K)(1,9)²=

L)
${20}^{ - 1} =$
M)
${( - 6)}^{ - 1} =$
n)
${11}^{ - 2} =$
o)
${2}^{ - 6} =$
P)
$(\frac{2}{3} ) {}^{ - 3} =$
q)
$( \frac{1}{3} ) {}^{ - 4}$
r)
$( \frac{4}{3}) {}^{ - 2} =$
2)calcule usando as propriedades da potenciação

a)
$4 {}^{2} \times 4 {}^{5} \times 4 {}^{ - 7} \times 4 {}^{3} =$
B)(3²)³=

C)
$2 {}^{0} \times 2 {}^{2} \times 2 {}^{3} \times 2 {}^{ - 6} \times 2 {}^{5} =$
D)6¹²÷6⁸=

E)3⁴÷3⁴=









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Answer 1

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1)

$\tt{a)}~\sf{7^2=49}\\\tt{b)}~\sf{9^0=1}\\\tt{c)}~\sf{-10^6=-1000000}\\\tt{d)}~\sf{(-10)^6=1000000}\\\tt{e)}~\sf{(-3)^2=9}$

$\tt{f)}~\sf{(-3)^3=-27}\\\tt{g)}~\sf{(-3)^4=81}\\\tt{h)}~\sf{(-0,3)^4=0,0081}\\\tt{i)}~\sf{\left(\\-\dfrac{3}{2}\right)^2=\dfrac{81}{4}}\\\tt{j)}~\sf{\left(-\dfrac{3}{4}\right)^3=-\dfrac{27}{64}}\\\tt{k)}~\sf{(1,9)^2=3,61}\\\tt{\ell)}~\sf{20^{-1}=\dfrac{1}{20}}\\\tt{m)}~\sf{(-6)^{-1}=-\dfrac{1}{6}}$

$\tt{n)}~\sf{11^{-2}=\dfrac{1}{121}}\\\tt{o)}~\sf{2^{-6}=\dfrac{1}{64}}\\\tt{q)}~\sf{\left(\dfrac{1}{3}\right)^{-4}=81}\\\tt{r)}~\sf{\left(\dfrac{4}{3}\right)^{-2}=\dfrac{9}{16}}$

2)

$\tt{a)}~\sf{4^2\cdot4^5\cdot4^{-7}\cdot4^3=4^{2+5-7+3}=4^3=64}\\\tt{b)}~\sf(3^2)^3={3^{2\cdot3}=3^6=729}\\\tt{c)}~\sf{2^0\cdot2^2\cdot2^3\cdot2^{-6}\cdot2^5=2^{0+2+3-6+5}=2^{4}=16}\\\tt{d)}~\sf{6^{12}\div6^8=6^{12-8}=6^4=1296}\\\tt{e)}~\sf{3^4\div3^4=3^{4-4}=3^0=1}$