Question

exercicios de fixacao ax+7=13
b x-5=10
c 2x=24
d-2×=10​

Answer 1

$a)x+7=13 \\ x = \frac{ - 7}{13} \\ </p><p>b)x-5=10 \\ x = \frac{10}{5} \\x = 2 \\ </p><p>c)2x=24 \\ x = \frac{24}{2} \\ x = 12 \\ </p><p>d)-2×=10 \\ x = \frac{10}{2} \\ x = 5$