Exercício em anexo matrizes
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Para resolver matriz de ordem 2 , basta multiplicar a diagonal principal e subtrair pela secundária :
![a)\\\\[(-3)(-1)-(4)(a)]+ [(b)(c)-(3)(-5)]=d\\3-4a+bc+15=d\\\\\boxed{-4a+bc=d-18}](https://tex.z-dn.net/?f=a%29%5C%5C%5C%5C%5B%28-3%29%28-1%29-%284%29%28a%29%5D%2B+%5B%28b%29%28c%29-%283%29%28-5%29%5D%3Dd%5C%5C3-4a%2Bbc%2B15%3Dd%5C%5C%5C%5C%5Cboxed%7B-4a%2Bbc%3Dd-18%7D "a)\\\\[(-3)(-1)-(4)(a)]+ [(b)(c)-(3)(-5)]=d\\3-4a+bc+15=d\\\\\boxed{-4a+bc=d-18}")
![b)\\\\(-4)(1)-(3)(a)+2([(b)(2)-(4)(-3)])=(12)(d)-(c)(1)\\4-3a+2(2b+12)=12d-c\\4-3a+4b+24=12d-c\\\\\boxed{-3a+4b=12d-c-28}](https://tex.z-dn.net/?f=b%29%5C%5C%5C%5C%28-4%29%281%29-%283%29%28a%29%2B2%28%5B%28b%29%282%29-%284%29%28-3%29%5D%29%3D%2812%29%28d%29-%28c%29%281%29%5C%5C4-3a%2B2%282b%2B12%29%3D12d-c%5C%5C4-3a%2B4b%2B24%3D12d-c%5C%5C%5C%5C%5Cboxed%7B-3a%2B4b%3D12d-c-28%7D "b)\\\\(-4)(1)-(3)(a)+2([(b)(2)-(4)(-3)])=(12)(d)-(c)(1)\\4-3a+2(2b+12)=12d-c\\4-3a+4b+24=12d-c\\\\\boxed{-3a+4b=12d-c-28}")
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