Question

EXERCÍCIO
Determine a força resultante dos vetores
anexo a seguir

Answer 1

Resposta:

a)

fórmula:

F^2= F1^2 + F2^2

F^2= 4^2+3^2

F^2= 16+9

F^2 = 25

F = √25

F= 5

C) fórmula leis do cosx

F^2 = F1^2+ F2^2+ 2.F1.F2.cos120°

F^2= 4^2 + 3^2+ 2.4.3.0,5

F^2= 37

F= √37

F≈6.0

espero ter ajudado!! bons estudos

Answer 2

Explicação:

a)

$\sf (F_{R})^2=(F_1)^2+(F_2)^2+2\cdot F_1\cdot F_2\cdot cos~\beta$

$\sf (F_{R})^2=3^2+4^2+2\cdot3\cdot4\cdot cos~90^{\circ}$

$\sf (F_{R})^2=3^2+4^2+2\cdot3\cdot4\cdot0$

$\sf (F_{R})^2=9+16+0$

$\sf (F_{R})^2=25$

$\sf F_R=\sqrt{25}$

$\sf \red{F_R=5~N}$

b)

$\sf (F_{R})^2=(F_1)^2+(F_2)^2+2\cdot F_1\cdot F_2\cdot cos~\beta$

$\sf (F_{R})^2=3^2+4^2+2\cdot3\cdot4\cdot cos~120^{\circ}$

$\sf (F_{R})^2=3^2+4^2+2\cdot3\cdot4\cdot(-0,5)$

$\sf (F_{R})^2=9+16-12$

$\sf (F_{R})^2=13$

$\sf \red{F_R=\sqrt{13}~N}$