Question

Exercício 4) Calcule as potências.
A-
${27}^{1)3}$
B-
${4}^{3)2}$
C-
${32}^{2)5}$
​

Answer 1

Resposta:

${27}^{ \frac{1}{3} } = \sqrt[3]{27} = 3 \\ {4}^{ \frac{3}{2} } = \sqrt[2]{ {4}^{3} } = \sqrt{64} = 8 \\ {32}^{ \frac{2}{5} } = \sqrt[5]{ {32}^{2} } = \sqrt[5]{ {( {2}^{5}) }^{2} } = \sqrt[5]{ {2}^{10} } = {2}^{ \frac{10}{5} } = {2}^{2} = 4$