Question

Exercicio 10. Determine o valor de x na figura 4 3​

Answer 1

Teorema de Pitágoras

Y²=1²+1²

Y²=1+1

Y²=2

$y = \sqrt{2}$

a=y²+2²

$a = ( \sqrt{2} ) {}^{2} + 2 {}^{2} \\ a = 2 + 4 \\ a = \sqrt{6}$

b²=a²+3²

$b {}^{2} = ( \sqrt{ {6}^{} } ) {}^{2} + 3 {}^{2} \\ b {}^{2} = 6 + 9 \\ b {}^{2} = 15 \\ b = \sqrt{15}$

X²=b²+4²

${x}^{2} = ( \sqrt{15} ) {}^{2} + 4 {}^{2} \\ x {}^{2} = 15 + 16 \\ x {}^{2} = 31 \\ x = \sqrt{31}$

X Vale raiz de 31