Question

Eu queria ajuda de vcs,mim ajuda.
Bhaskara.
${x}^{2} - 8x + 15 = 0$






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Answer 1

Resposta:

${x}^{2} - 8x + 15 = 0 \\ \\ Bháskara \\ \\ Delta = {b}^{2} - 4ac \\ \\ a = 1 \: \: b = - 8 \: \: c = 15 \\ Delta = {( - 8)}^{2} - 4(1)(15) \\ Delta = 64 - 60 \\ Delta = 4 \\ \\ Bháskara \\ \frac{ - b \frac{ + }{} \sqrt{Delta} }{2a} \\ \\ \frac{ - ( - 8) \frac{ + }{} \sqrt{4} }{2(1)} \\ \\ \frac{8 \frac{ + }{} 2}{2} \\ \\ x1 = \frac{8 + 2}{2} = \frac{10}{2} = 5 \\ \\ x2 = \frac{8 - 2}{2} = \frac{6}{2} = 3$

Raízes são: 5 e 3

Bons Estudos!

Answer 2

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$\Large\boxed{\boxed{\boxed{{Ola\´\ }}}}$

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$BhaˊskaraDelta=b2−4aca=1b=− \\ c=15Delta=(−8)2−4(1 \\ (15)Delta=64−60Delta=4Bhaˊskara2a−b+Delta2(1)−(−8)+428+2 \\ x1=28+2=210=5x2=28−2=26=3 \\ </p><p></p><p></p><p></p><p></p><p></p><p>$

$Raízes \: são: \: 5 \: e \: 3$

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$\Large\boxed{\boxed{\boxed{{꧁ EmBaixaDor ꧂. \: \´\ }}}}$