Question

estima-se que,em x meses a partir de agora, a população de certa comunidade será de p(x)=x ao quadrado +20x+8.000.Qual a taxa de variação médoada população no intervalo de2 a 5 meses?

Answer 1

$p(x)=x^2+20x+8000\\\\\\\dfrac{p(5)-p(2)}{5-2}=\ ?\\\\\\\\\begin{matrix}p(5)=(5)^2+20(5)+8000\\\\p(5)=25+100+8000\\\\p(5)=8125\end{matrix}\qquad\qquad\qquad\begin{matrix}p(2)=(2)^2+20(2)+8000\\\\p(2)=4+40+8000\\\\p(2)=8044\end{matrix}\\\\\\\\\dfrac{p(5)-p(2)}{5-2}=\ ?\\\\\\\dfrac{8125-8044}{5-2}=\\\\\\\dfrac{81}{3}=\boxed{27\mathrm{\ popula\text{\c{c}}\tilde{a}o}/\mathrm{m\hat{e}s}}$