Matemática, perguntado por perguntador2823, 8 meses atrás


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Anexos:

Soluções para a tarefa

Respondido por Usuário anônimo
2

Resposta:

A = \left[\begin{array}{ccc}2&1\\-3&4\end{array}\right]

B = \left[\begin{array}{ccc}0&-1\\2&5\end{array}\right]

C = \left[\begin{array}{ccc}3&0\\6&1\end{array}\right]

A)

\left[\begin{array}{ccc}2&1\\-3&4\end{array}\right] - \left[\begin{array}{ccc}0&-1\\2&5\end{array}\right]\\\\\\= \left[\begin{array}{ccc}2&2\\-5&-1\end{array}\right]

B)

Bt = \left[\begin{array}{ccc}0&2\\-1&5\end{array}\right]

Logo:

\left[\begin{array}{ccc}2&1\\-3&4\end{array}\right] - \left[\begin{array}{ccc}0&2\\-1&5\end{array}\right] - \left[\begin{array}{ccc}3&0\\6&1\end{array}\right]\\\\\\=  \left[\begin{array}{ccc}2&-1\\-2&-1\end{array}\right] - \left[\begin{array}{ccc}3&0\\6&1\end{array}\right]\\\\\\ = \left[\begin{array}{ccc}-1&-1\\-8&-2\end{array}\right]

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