Question

Está certo?????????
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Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{-3x^2 - 8x + 3 = 0}$

$\mathsf{\Delta = b^2 - 4.a.c}$

$\mathsf{\Delta = (-8)^2 - 4.(-3).3}$

$\mathsf{\Delta = 64 + 36}$

$\mathsf{\Delta = 100}$

$\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{8 \pm \sqrt{100}}{-6} \rightarrow \begin{cases}\mathsf{x' = \dfrac{8 + 10}{-6} = \dfrac{18}{-6} = -3}\\\\\mathsf{x'' = \dfrac{8 - 10}{-6} = \dfrac{-2}{-6} = \dfrac{1}{3}}\end{cases}}$

$\mathsf{S = \left\{-3\:;\dfrac{1}{3}\right\}}$

Answer 2

Resposta:

S= {-3, 1/3}

Explicação passo-a-passo:

-3x²-8x+3=0

a= -3, b=-8 e c=3

delta =b²-4ac

delta= (-8)²-4•-3•3=64+36=100

$\sqrt{100} = 10$

x'=[-(-8)+10]/2.-3

x'=[8+10)/-6

x'=18/-6

x'=-3

x"=[-(-8)-10]/2.-3

x"=[+8-10]/-6

x"=-2/-6

x"=1/3