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Anexos:
Soluções para a tarefa
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Bom dia Jailson!
Solução!
Esse limite pode ser calculado unicamente por substituição.
A)
![\displaystyle \lim_{x \to1} (x+1)\\\\\\
\displaystyle \lim_{x \to1} (1+1)\\\\\\
\displaystyle \lim_{x \to1} 2\\\\\\\\\
\boxed {\displaystyle \lim_{x \to1} (x+1)=2}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%28x%2B1%29%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%281%2B1%29%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+2%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed+%7B%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%28x%2B1%29%3D2%7D%0A+++ "\displaystyle \lim_{x \to1} (x+1)\\\\\\
\displaystyle \lim_{x \to1} (1+1)\\\\\\
\displaystyle \lim_{x \to1} 2\\\\\\\\\
\boxed {\displaystyle \lim_{x \to1} (x+1)=2}")
No exercício b ,vamos fatorar a equação incompleta que esta no denominador!
![( x^{2} -1)=(x+1)\times(x-1)\\\\\
\displaystyle \lim_{x \to1} \frac{ (x^{2} +1)}{(x-1)}} \\\\\\
\displaystyle \lim_{x \to1} \frac{ (x+1)\times(x-1))}{(x-1)}} \\\\\\
\displaystyle \lim_{x \to1} (x+1) \\\\\\
\displaystyle \lim_{x \to1} (1+1) \\\\\\
\displaystyle \lim_{x \to1} 2 \\\\\\\\\\
\boxed{Resposta:\displaystyle \lim_{x \to1} \frac{ (x^{2} +1)}{(x-1)}=2}} \\\\\\](https://tex.z-dn.net/?f=%28+x%5E%7B2%7D+-1%29%3D%28x%2B1%29%5Ctimes%28x-1%29%5C%5C%5C%5C%5C%0A%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%5Cfrac%7B+%28x%5E%7B2%7D+%2B1%29%7D%7B%28x-1%29%7D%7D+%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%5Cfrac%7B+%28x%2B1%29%5Ctimes%28x-1%29%29%7D%7B%28x-1%29%7D%7D+%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%28x%2B1%29+%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%281%2B1%29+%5C%5C%5C%5C%5C%5C%0A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+2+%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A%5Cdisplaystyle+%5Clim_%7Bx+%5Cto1%7D+%5Cfrac%7B+%28x%5E%7B2%7D+%2B1%29%7D%7B%28x-1%29%7D%3D2%7D%7D+%5C%5C%5C%5C%5C%5C%0A "( x^{2} -1)=(x+1)\times(x-1)\\\\\
\displaystyle \lim_{x \to1} \frac{ (x^{2} +1)}{(x-1)}} \\\\\\
\displaystyle \lim_{x \to1} \frac{ (x+1)\times(x-1))}{(x-1)}} \\\\\\
\displaystyle \lim_{x \to1} (x+1) \\\\\\
\displaystyle \lim_{x \to1} (1+1) \\\\\\
\displaystyle \lim_{x \to1} 2 \\\\\\\\\\
\boxed{Resposta:\displaystyle \lim_{x \to1} \frac{ (x^{2} +1)}{(x-1)}=2}} \\\\\\")
Bom dia!
Bons estudos!
Solução!
Esse limite pode ser calculado unicamente por substituição.
A)
No exercício b ,vamos fatorar a equação incompleta que esta no denominador!
Bom dia!
Bons estudos!
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