Question

essa está difícil!
5(x²+x-2) - x(x-3) = 3x(x+2) - 11

Answer 1

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$5( x^{2} +x-2)-x(x-3)=3x(x+2)-11 \\ 5x^2+5x-10-x^2+3x=3x^2+6x-11 \\ \\ 5x^2-x^2-3x^2+5x+3x-6x-10+11= \\ \\ x^2+2x+1=0$

Δ=b²-4ac
Δ=2²-4(1)
Δ=4-4
Δ=0

$x'=x"=- \frac{b}{a} \\ \\ x'=x"=- \frac{2}{2} =-1$

A raiz é (-1)

Answer 2

5(x^2+x-2)-x(x-3)=3x(x+2)-11
5x^2+5x-10-x^2+3x=3x^2+6x-11
5x^2-x^2-3x^2+5x+3x-6x=-11+10
5x^2-4x^2+8x-6x=-1
x^2+2x=-1
x^2+2x+1=0
delta=b^2-4ac
delta=2^2-4.1.1
delta=4-4
delta=0
x=-b-/+ raiz de delta/2a
x=-2-0/2.1
x=-2/2
x=-1