escreve a equaçao da circunferencia de centro C e raio r nos seguintes casos a. C(-3, -2) e r=7 e b. C(1, -4) e r=3
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Equação geral de uma circunferência é: 
Onde a e b são as coordenadas do centro.
Substituindo os dados na equação temos:
![\mathsf{a-}\\\\\mathsf{[x-(-3)]^2+[y-(-2)]=7^2}\\\mathsf{(x+3)^2+(y+2)^2=49}\\\mathsf{x^2+6x+9+y^2+4y+4=49}\\\mathsf{x^2+6x+y^2+4y=49-13}\\\\\boxed{\mathsf{x^2+6x+y^2+4y=36}}](https://tex.z-dn.net/?f=%5Cmathsf%7Ba-%7D%5C%5C%5C%5C%5Cmathsf%7B%5Bx-%28-3%29%5D%5E2%2B%5By-%28-2%29%5D%3D7%5E2%7D%5C%5C%5Cmathsf%7B%28x%2B3%29%5E2%2B%28y%2B2%29%5E2%3D49%7D%5C%5C%5Cmathsf%7Bx%5E2%2B6x%2B9%2By%5E2%2B4y%2B4%3D49%7D%5C%5C%5Cmathsf%7Bx%5E2%2B6x%2By%5E2%2B4y%3D49-13%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7Bx%5E2%2B6x%2By%5E2%2B4y%3D36%7D%7D "\mathsf{a-}\\\\\mathsf{[x-(-3)]^2+[y-(-2)]=7^2}\\\mathsf{(x+3)^2+(y+2)^2=49}\\\mathsf{x^2+6x+9+y^2+4y+4=49}\\\mathsf{x^2+6x+y^2+4y=49-13}\\\\\boxed{\mathsf{x^2+6x+y^2+4y=36}}")
![\mathsf{b-}\\\\\mathsf{(x-1)^2+[y-(-4)]^2=3^2}\\\mathsf{x^2-2x+1+y^2+8y+16=9}\\\mathsf{x^2-2x+y^2+8y=9-17}\\\\\boxed{\mathsf{x^2-2x+y^2+8y=-8}}](https://tex.z-dn.net/?f=%5Cmathsf%7Bb-%7D%5C%5C%5C%5C%5Cmathsf%7B%28x-1%29%5E2%2B%5By-%28-4%29%5D%5E2%3D3%5E2%7D%5C%5C%5Cmathsf%7Bx%5E2-2x%2B1%2By%5E2%2B8y%2B16%3D9%7D%5C%5C%5Cmathsf%7Bx%5E2-2x%2By%5E2%2B8y%3D9-17%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7Bx%5E2-2x%2By%5E2%2B8y%3D-8%7D%7D "\mathsf{b-}\\\\\mathsf{(x-1)^2+[y-(-4)]^2=3^2}\\\mathsf{x^2-2x+1+y^2+8y+16=9}\\\mathsf{x^2-2x+y^2+8y=9-17}\\\\\boxed{\mathsf{x^2-2x+y^2+8y=-8}}")
Dúvidas? comente
Onde a e b são as coordenadas do centro.
Substituindo os dados na equação temos:
Dúvidas? comente
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