Escreva uma PA de razão -3, onde a soma dos 100 primeiros termos é -14350
POR FAVOR ME AJUDEM
Soluções para a tarefa
Resposta:Segue as contas abaixo na explicação
Explicação passo-a-passo:
S100=-14350,r=-3,a1=?,a100=?
an=a1+(n-1).r
a100=a1+(100-1).(-3)
a100=a1+99.(-3)
a100=a1-297
Sn=(a1+an).n/2
-14350=(a1+a1-297).100/2
-14350=(2.a1-297).100/2
-14350=200.a1-29700/2
200.a1-29700=(-14350).2
200.a1-29700=-28700
200.a1-29700+29700=-28700+29700
200.a1=1000
a1=1000/200
a1=5
an=a1+(n-1).r
a100=5+(100-1).(-3)
a100=5+99.(-3)
a100=5-297
a100=-292
PA(5,2,-1,-4,-7,-10,-13,-16,-19,-22,-25,-28,-31,-34,-37,-40,-43,-46,-49,-52,-55,-58,-61,-64,-67,-70,-73,-76,-79,-82,-85,-88,-91,-94,-97,-100,-103,-106,-109,-112,-115,-,118,-121,-124,-127,-130,-,133,-136,-139,-142,-145,-148,-151,-154,-157,-160,-163,-166,-169,-172,-1,75,-178,-181,-184,-187,-190,-193,-196,-199,-202,-205,-208,-211,-214,-217,-220,-223,-226,-229,-232,-235,-238,-241,-244,-247,-250,-253,-256,-259,-262,-265,-268,-,271,-274,-,277,-280,-283,-286,-289,-292)