Question

escreva os seis primeiros termos da PA com r= 11 e A1= 5​

Answer 1

Resposta:

razão =11  e a1=5

an=a1+(n-1)*r

a1=5

a2=5+11=  16

a3=16+11= 27

a4=27+11 = 38

a5=38+11= 49

a6=49+11= 60

Answer 2

Resposta:

PA ={5,16,27,38,49,60}

Explicação passo-a-passo:

$a_{n}=a_{1}+(n-1)r\\\\a_{1}=5\\r = 11\\a_{n}=5+(n-1).11\\\\\\a_{2}=5+(2-1).11=5+11=16\\a_{3}=5+(3-1).11=5+2.11=5+22=27\\\\a_{4}=5+(4-1).11=5+3.11=5+33=38\\\\a_{5}=5+(5-1).11=5+4.11=5+44=49\\\\a_{6}=5+(6-1).11=5+5.11=5+55=60$