Question

escreva como uma unica potencia de base 5 
(625)^2.25^3.125^-8/ 3125^-2:25^5

Answer 1

$\frac{(625)^2.25^3.125^{-8}}{ 3125^{-2}:25^5}=\frac{(5^4)^2.(5^2)^3.(5^3)^{-8}}{(5^5)^{-2}:(5^2)^5}=\frac{5^8.5^6.5^{-15}}{5^{-10}:5^{10}}=\frac{5^{-1}}{5^{-20}}=5^{19}$