Escreva cada expressão por meio de um polinômio na forma reduzida
a) ![(a+1) ^{2} + (2a) ^{3} (a+1) ^{2} + (2a) ^{3}](https://tex.z-dn.net/?f=%28a%2B1%29+%5E%7B2%7D++%2B+%282a%29+%5E%7B3%7D+)
b) ![(2a+b)² - (a-b)² (2a+b)² - (a-b)²](https://tex.z-dn.net/?f=%282a%2Bb%29%C2%B2+-+%28a-b%29%C2%B2)
c) ![5 . (-a+b) ^{2} - (b+3a) ^{2} 5 . (-a+b) ^{2} - (b+3a) ^{2}](https://tex.z-dn.net/?f=5+.+%28-a%2Bb%29+%5E%7B2%7D++-+%28b%2B3a%29+%5E%7B2%7D+)
d) ![(-a-b) ^{2} -8ab-a ^{2} (-a-b) ^{2} -8ab-a ^{2}](https://tex.z-dn.net/?f=%28-a-b%29+%5E%7B2%7D+-8ab-a+%5E%7B2%7D+)
e) ![(3a+6b).(2a-2)-8a ^{2} (3a+6b).(2a-2)-8a ^{2}](https://tex.z-dn.net/?f=%283a%2B6b%29.%282a-2%29-8a+%5E%7B2%7D+)
f) ![(a ^{3} -b ^{2} ) ^{2} - 2 . (b ^{4} - a ^{6})+2a ^{3} b ^{2} (a ^{3} -b ^{2} ) ^{2} - 2 . (b ^{4} - a ^{6})+2a ^{3} b ^{2}](https://tex.z-dn.net/?f=%28a+%5E%7B3%7D+-b+%5E%7B2%7D+%29+%5E%7B2%7D++-+2+.+%28b+%5E%7B4%7D+-+a+%5E%7B6%7D%29%2B2a+%5E%7B3%7D+b+%5E%7B2%7D+)
o objetivo e reduzir as expressões por meio de polinômios por isso elas não possuem resultado final
Soluções para a tarefa
Respondido por
237
a)
vamos usar o trinômio quadrado perfeito
![(a+b)^{2} = a^{2} +2ab+ b^{2} (a+b)^{2} = a^{2} +2ab+ b^{2}](https://tex.z-dn.net/?f=%28a%2Bb%29%5E%7B2%7D+%3D++a%5E%7B2%7D+%2B2ab%2B+b%5E%7B2%7D)
![(a-b)^{2} = a^{2} -2ab+ b^{2} (a-b)^{2} = a^{2} -2ab+ b^{2}](https://tex.z-dn.net/?f=%28a-b%29%5E%7B2%7D+%3D++a%5E%7B2%7D+-2ab%2B+b%5E%7B2%7D)
![8a^{3} + a^{2}+2a+1 8a^{3} + a^{2}+2a+1](https://tex.z-dn.net/?f=8a%5E%7B3%7D+%2B+a%5E%7B2%7D%2B2a%2B1)
b)![(2a+b)^{2} - (a-b)^{2} (2a+b)^{2} - (a-b)^{2}](https://tex.z-dn.net/?f=+%282a%2Bb%29%5E%7B2%7D+-+%28a-b%29%5E%7B2%7D)
usando trinômio novamente
![4a^{2} + 4ab + b^{2} -(a^{2} -2ab+ b^{2}) 4a^{2} + 4ab + b^{2} -(a^{2} -2ab+ b^{2})](https://tex.z-dn.net/?f=4a%5E%7B2%7D+%2B+4ab+%2B++b%5E%7B2%7D++-%28a%5E%7B2%7D+-2ab%2B+b%5E%7B2%7D%29)
![4 a^{2} + 4ab + b^{2} - a^{2} +2ab- b^{2} 4 a^{2} + 4ab + b^{2} - a^{2} +2ab- b^{2}](https://tex.z-dn.net/?f=4+a%5E%7B2%7D+%2B+4ab+%2B++b%5E%7B2%7D++-+a%5E%7B2%7D+%2B2ab-+b%5E%7B2%7D)
![3 a^{2} + 6ab 3 a^{2} + 6ab](https://tex.z-dn.net/?f=3+a%5E%7B2%7D+%2B+6ab)
c)
aplicando trinômio quadrado perfeito
![5.( a^{2} - 2ab + b^{2} ) - (b^{2} + 6ab + 9 a^{2} ) 5.( a^{2} - 2ab + b^{2} ) - (b^{2} + 6ab + 9 a^{2} )](https://tex.z-dn.net/?f=5.%28+a%5E%7B2%7D+-+2ab+%2B++b%5E%7B2%7D++%29+-+%28b%5E%7B2%7D+%2B+6ab+%2B+9+a%5E%7B2%7D+%29)
![5a^{2} - 10ab + 5b^{2} - b^{2} - 6ab - 9 a^{2} 5a^{2} - 10ab + 5b^{2} - b^{2} - 6ab - 9 a^{2}](https://tex.z-dn.net/?f=5a%5E%7B2%7D+-+10ab+%2B++5b%5E%7B2%7D+-+b%5E%7B2%7D+-+6ab+-+9+a%5E%7B2%7D)
![-4 a^{2} - 16ab + 4b^{2} -4 a^{2} - 16ab + 4b^{2}](https://tex.z-dn.net/?f=-4+a%5E%7B2%7D+-+16ab+%2B++4b%5E%7B2%7D)
d)![(-a-b)^{2} - 8ab - a^{2} (-a-b)^{2} - 8ab - a^{2}](https://tex.z-dn.net/?f=%28-a-b%29%5E%7B2%7D+-+8ab+-++a%5E%7B2%7D)
![(a^{2} +2ab + b^{2}) - 8ab - a^{2} (a^{2} +2ab + b^{2}) - 8ab - a^{2}](https://tex.z-dn.net/?f=+%28a%5E%7B2%7D+%2B2ab+%2B++b%5E%7B2%7D%29+-+8ab+-++a%5E%7B2%7D)
![-6ab + b^{2} -6ab + b^{2}](https://tex.z-dn.net/?f=-6ab+%2B+b%5E%7B2%7D)
e)![(3a+6b).(2a-2)-8 a^{2} (3a+6b).(2a-2)-8 a^{2}](https://tex.z-dn.net/?f=%283a%2B6b%29.%282a-2%29-8+a%5E%7B2%7D)
aplicando a propriedade distributiva
![6 a^{2} -6a +12ab -12b-8 a^{2} 6 a^{2} -6a +12ab -12b-8 a^{2}](https://tex.z-dn.net/?f=6+a%5E%7B2%7D+-6a+%2B12ab+-12b-8+a%5E%7B2%7D)
![-2 a^{2}-6a(1-2b) -12b -2 a^{2}-6a(1-2b) -12b](https://tex.z-dn.net/?f=-2+a%5E%7B2%7D-6a%281-2b%29+-12b)
f)
aplicando a propriedade distributiva e o trinômio
![( a^{6} - 2 a^{3} b^{2} + b^{4} ) -2b^{4} + 2a^{6} + 2 a^{3} b^{2} ( a^{6} - 2 a^{3} b^{2} + b^{4} ) -2b^{4} + 2a^{6} + 2 a^{3} b^{2}](https://tex.z-dn.net/?f=%28+a%5E%7B6%7D+-+2+a%5E%7B3%7D++b%5E%7B2%7D+%2B++b%5E%7B4%7D++%29+-2b%5E%7B4%7D+%2B+2a%5E%7B6%7D+%2B+2+a%5E%7B3%7D++b%5E%7B2%7D)
![3a^{6} b^{2} -b^{4} 3a^{6} b^{2} -b^{4}](https://tex.z-dn.net/?f=3a%5E%7B6%7D+b%5E%7B2%7D++++-b%5E%7B4%7D+)
vamos usar o trinômio quadrado perfeito
b)
usando trinômio novamente
c)
aplicando trinômio quadrado perfeito
d)
e)
aplicando a propriedade distributiva
f)
aplicando a propriedade distributiva e o trinômio
iamamidreami:
Se ajudou, escolha como melhor resposta!
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