Question

Escreva as equações na forma geral e
resolva-as (3x+1)^2 +(x-2)(x+1)=-1

Answer 1

(3x + 1)² + (x - 2).(x + 1) = - 1
9x² + 2.3x + 1 + x² + x - 2x - 2 = - 1
9x² + 6x + 1 + x² - x - 2 + 1 = 0
9x² + x² + 6x - x + 1 + 1 - 2 = 0
10x² + 5x + 2 - 2 = 0
10x² + 5x = 0
x(10x + 5) = 0
x = 0

ou

10x + 5 = 0
10x = - 5 (:5)
2x = - 1
x = - 1
        2

x = 0 e x = - 1/2

R.: {0, - 1/2}