Question

Escreva as equações abaixo na forma geral e resolva em R:
6) X(X + 3) - 40 = 0
7) 10 + x(x - 2) = 2
9) (x - 1)(x + 5) = 7
8) 4 + x(x-4) = x
10) ( x - 3)(x + 2) = - 4​

Answer 1

Resposta:

a) x(x+3)-40-O

X'2+3x-40=0

cielta-b^2-4ac

delta=3^2-41(-40)

delta=9+160

delta=169

x=-b-/+ raiz de delto/2a

x=3-13/2.1

x= 16/2 Y-8

X=3-13/2.1

X10/2 x-5

b) 10+x(x-2)=2

10+x2-2x=2

x2-2x-10-2

x^2-2x-8=0 delte-b^2-4ac

delta=1-272-4.1.8

delte-4-32 delte=28

della negativo não há raizes reals.

c) 4+x{X-4= 4+x^2-4x=X

X 2-4%-x+4 x*2 5x+4=0

delta=b2-48c

delta-4-5) 2-4.1.4 delta=25-16

delta=9

X-b-/+ raiz de delta/2a X-(-5) 3/2.1

x=5-3/2

X-212

x-1 X=-(-5)+3:2.1 x-5-3/2

x=8/2

x=4 X-4 d) x x-5)-2x=28

X2-5x-2x=28

x*2-3x=28 x*2-3x-28-0

delta=b^2-4oc

delta-3 2-4,1.(-28) delta-9-112

delta=121

X=--!+ raiz de delta 28

X=-3-1/2.1

14/2 X-7

X=-3+11/2.1

x-8/2 X-4

e) 2x(x+3)=x^2+3x-10

2x^2-6x=x2-3x+10 2x 2-x*2+6x-3x=10

x2-3x-10 X'2-3x-10-0

delta-b2-400

delta=3 2-4.1.-10) delta=9+40

delta=49

X=-b-+ raiz de delta/2a

X-3-7/2.1

X-1012

X=-5 X=-3+7/2.1

X=4/2 x=2

espero ter ajudado bons estudos