Question

Escreva a matriz A= (aij) 6x4. Na qual aij= (i-5j)^2​

Answer 1

Resposta:

Explicação passo-a-passo:

a11=(1-5.1)^2=(-4)^2=16

a12=(1-5.2)^2=(-9)^2=81

a13=(1-5.3)^2=(-14)^2=196

a14=(1-5.4)^2=(-19)^2=361

a21=(2-5.1)^2=(-3)^2=9

a22=(2-5.2)^2=(-8)^2=64

a23=(2-5.3)^2=(-13)^2=169

a24=(2-5.4)^2=(-18)^2=324

a31=(3-5.1)^2=(-2)^2=4

a32=(3-5.2)^2=(-7)^2=49

a33=(3-5.3)^2=(-12)^2=144

a34=(3-5.4)^2=(-17)^2=289

a41=(4-5.1)^2=(-1)^2=1

a42=(4-5.2)^2=(-6)^2=36

a43=(4-5.3)^2=(-11)^2=121

a44=(4-5.4)^2=(-16)^2=256

a51=(5-5.1)^2=(0)^2=0

a52=(5-5.2)^2=(-5)^2=25

a53=(5-5.3)^2=(-10)^2=100

a54=(5-5.4)^2=(-15)^2=225

a61=(6-5.1)^2=(1)^2=1

a62=(6-5.2)^2=(-4)^2=16

a63=(6-5.3)^2=(-9)^2=81

a64=(6-5.4)^2=(-14)^2=196

$\left[\begin{array}{cccc}16&81&196&361\\9&64&169&324\\4&49&144&289\\1&36&121&256\\0&25&100&225\\1&16&81&196\end{array}\right]$