Question

escreva a matriz A= (aij)4×3 | aij = i² + 3j - 2​

Answer 1

Explicação passo-a-passo:

A = a11 a12 a13

a21 a22 a23

a31 a32 a33

a41 a42 a43

aij= i² + 3.j -2

a11= 1²+3.1-2= 1+3-2= 4-2=2

a12= 1²+3.2-2= 1+6-2=7-2= 5

a13= 1²+3.3-2= 1+9-2= 10-2= 8

a21 = 2²+3.1-2= 4 +3-2= 7-2= 5

a22= 2²+3.2-2= 4+6-2= 10-2=8

a23= 2²+3.3-2= 4+9-2= 13-2= 11

a31= 3²+3.1-2= 9+3-2= 12-2=10

a32= 3²+3.2-2= 9+6-2= 15-2= 13

a33= 3²+3.3-2= 9+9-2= 18 -2= 16

a41= 4²+3.1-2= 16 +3-2= 19-2= 17

a42= 4²+3.2-2= 16 +6 -2= 22 -2= 20

a43= 4² +3.3-2= 16 +9 -2= 25 -2= 23

A = 2 5 8

5 8 11

10 13 16

17 20 23