Matemática, perguntado por vm4524090, 9 meses atrás

escreva a fração irredutível de cada fração dada

9/45

49/56

19/133

77/88

96/48

18/81

45/10

21/36

16/48

45/80

6/48

36/60

99/45

55/240

34/14

33/27

121/55

64/56

20/140

2/4

54/42

63/119

32/104

39/26

ajudem por favor

Soluções para a tarefa

Respondido por Usuário anônimo
4

Explicação passo-a-passo:

a) \sf \dfrac{9}{45}=\dfrac{9\div9}{45\div9}=\red{\dfrac{1}{5}}

b) \sf \dfrac{49}{56}=\dfrac{49\div7}{56\div7}=\red{\dfrac{7}{8}}

c) \sf \dfrac{19}{133}=\dfrac{19\div19}{133\div19}=\red{\dfrac{1}{7}}

d) \sf \dfrac{77}{88}=\dfrac{77\div11}{88\div11}=\red{\dfrac{7}{8}}

e) \sf \dfrac{96}{48}=\dfrac{96\div48}{48\div48}=\dfrac{2}{1}=\red{2}

f) \sf \dfrac{18}{81}=\dfrac{18\div9}{81\div9}=\red{\dfrac{2}{9}}

g) \sf \dfrac{45}{10}=\dfrac{45\div5}{10\div5}=\red{\dfrac{9}{2}}

h) \sf \dfrac{21}{36}=\dfrac{21\div3}{36\div3}=\red{\dfrac{7}{12}}

i) \sf \dfrac{16}{48}=\dfrac{16\div16}{48\div16}=\red{\dfrac{1}{3}}

j) \sf \dfrac{45}{80}=\dfrac{45\div5}{80\div5}=\red{\dfrac{9}{16}}

k) \sf \dfrac{6}{48}=\dfrac{6\div6}{48\div6}=\red{\dfrac{1}{8}}

l) \sf \dfrac{36}{60}=\dfrac{36\div12}{60\div12}=\red{\dfrac{3}{5}}

m) \sf \dfrac{99}{45}=\dfrac{99\div9}{45\div9}=\red{\dfrac{11}{5}}

n) \sf \dfrac{55}{240}=\dfrac{55\div5}{240\div5}=\red{\dfrac{11}{48}}

o) \sf \dfrac{34}{14}=\dfrac{34\div2}{14\div2}=\red{\dfrac{17}{7}}

p) \sf \dfrac{33}{27}=\dfrac{33\div3}{27\div3}=\red{\dfrac{11}{9}}

q) \sf \dfrac{121}{55}=\dfrac{121\div11}{55\div11}=\red{\dfrac{11}{5}}

r) \sf \dfrac{64}{56}=\dfrac{64\div8}{56\div8}=\red{\dfrac{8}{7}}

s) \sf \dfrac{20}{140}=\dfrac{20\div20}{140\div20}=\red{\dfrac{1}{7}}

t) \sf \dfrac{2}{4}=\dfrac{2\div2}{4\div2}=\red{\dfrac{1}{2}}

u) \sf \dfrac{54}{42}=\dfrac{54\div6}{42\div6}=\red{\dfrac{9}{7}}

v) \sf \dfrac{63}{119}=\dfrac{63\div7}{119\div7}=\red{\dfrac{9}{17}}

w) \sf \dfrac{32}{104}=\dfrac{32\div8}{104\div8}=\red{\dfrac{4}{13}}

x) \sf \dfrac{39}{26}=\dfrac{39\div13}{26\div13}=\red{\dfrac{3}{2}}


StefanyCortes: ME AJUDA EM QUIMICA POR FAVOR!!!

O ácido fosfórico (H3PO4) pode dissociar-se de até 3 prótons, com pKas de 2,2, 7,2 e 12,3. Portanto, qual das espécies predomina no sangue (pH 7,4)?
a) H2PO4
b) PO43
c) HPO42
d) H3PO4
vm4524090: eu não estudo química ainda desculpa
StefanyCortes: Sim, eu pedi ao Pauloricardo
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