Question

Escreva A×B sendo:
A=
${64}^{0.66666...} \times {0.5}^{0.5}$
B=
${ ( {128}^{ \frac{1}{7} } + {81}^{ \frac{1}{4} } )}^{ - 2}$
​

Answer 1

$A = 64^{2/3}.(\frac{1}{2})^{\frac{1}{2}} \\B = 128^{\frac{1}{7}}+81^{\frac{1}{4}$

 Propriedade utilizada: $x^{\frac{a}{b}} <=> \sqrt[b]{x^a}$

$(64^{2/3}.(\frac{1}{2})^{\frac{1}{2}}).(128^{\frac{1}{7}}+81^{\frac{1}{4}})\\(\sqrt[3]{64^2}.\frac{1}{\sqrt{2} }).(\sqrt[7]{128}+\sqrt[4]{81})\\ (\sqrt[3]{64.64}.\frac{\sqrt{2}}{2}).(2+3)\\(\sqrt[3]{64}.\sqrt[3]{64}.\frac{\sqrt{2}}{2}).5\\(4.4.\frac{\sqrt{2}}{2}).5\\(8.\sqrt{2}).5\\40.\sqrt{2}$

Dúvidas só perguntar!