Question

escalonamento:
b) x+2y+z=7
2x-y+4z=17
3x-2y+2z=14

Answer 1

x – 2y + z = 7 

2x – y + 4z = 17 

3x – 2y +2z = 14 

|1 -2 1 7| 
|2 -1 4 17| 
|3 -2 2 14| 

L2 -->L2 - 2L1 

|1 -2 1 7| 
|0 3 2 3| 
|3 -2 2 14| 

L3 -->L3 - 3L1 


|1 -2 1 7| 
|0 3 2 3| 
|0 4 -1 -7| 

L2 -->L2 + 2L3 

|1 -2 1 7| 
|0 11 0 -11| 
|0 4 -1 -7| 

L2 -->L2 /11 


|1 -2 1 7| 
|0 1 0 -1| 
|0 4 -1 -7| 

L3 --> - L3 + 4L2 

|1 -2 1 7| 
|0 1 0 -1| 
|0 0 1 3| 

L1 --> L1 - L3 

|1 -2 0 4| 
|0 1 0 -1| 
|0 0 1 3| 

L1 --> L1 + 2L2 

|1 0 0 2| 
|0 1 0 -1| 
|0 0 1 3| 

x = 2 
y = -1