Question

Esboce os gráficos das funções
sendo f: R -- R determine os gráficos

1) f(x) = x+2
f(1) =
f(0) =
f(-1) =


2) f(x) = x-1
f(1) =
f(0) =
f(-1) =

3) f(x) = -x+1
f(1) =
f(0) =
f(-1)

4) f(x) = 3x-2
f(1) =
f(0) =
f(-1)
​

Answer 1

Explicação passo-a-passo:

1) f(x) = x+2

f(1) = 1 + 2 = + 1 + 2 = + 1 + 2 = 3 (1, 3)

f(0) = 0 + 2 = + 0 + 2 = + 0 + 2 = 2 (0, 2)

f(-1) = (-1) + 2 = - 1 + 2 = - 1 + 2 = 1 (-1, 1)

2) f(x) = x-1

f(1) = 1 - 1 = + 1 - 1 = + 1 - 1 = 0 (1, 0)

f(0) = 0 - 1 = + 0 - 1 = + 0 - 1 = -1 (0, -1)

f(-1) = (-1) - 1 = - 1 - 1 = - 1 - 1 = -2 (-1, -2)

3) f(x) = -x+1

f(1) = - 1 + 1 = - 1 + 1 = - 1 + 1 = 0 (1, 0)

f(0) = 0 + 1 = + 0 + 1 = + 0 + 1 = 1 (0, 1)

f(-1) = (-1) + 1 = + 1 + 1 = + 1 + 1 = 2 (-1, 2)

4) f(x) = 3x-2

f(1) = 3.1 - 2 = + 3 - 2 = + 3 - 2 = 1 (1, 1)

f(0) = 3.0 - 2 = + 0 - 2 = + 0 - 2 = -2 (0, -2)

f(-1) = 3. (-1) - 2 = - 3 - 2 = - 3 - 2 = -5 (-1, -5)