Question

Equacoes do segundo 2 grau determinando as raizes se existir
X2 - 5X + 6 = 0

Answer 1

x² - 5 x + 6 = 0
Δ = b² - 4.a.c
Δ = (-5)² -4.1.6
Δ = 25 - 24
Δ = 1 ⇒√1 = 1
x = - b + ou - 1/2.1
x´= -(-5) + 1/2 ⇒5 + 1/2 = 6/2 = 3
x´´ = 5 - 1 /2 ⇒4/2 = 2
S = {1 ; 2 }

Answer 2

Δ = b² - 4.a.c Δ = (-5)² - 4.1.6 Δ = 25 - 24 Δ = 1 ⇒√1 = 1 x= - b + ou - √Δ /2.a x= -(-5) + ou - √1/2.1 x= 5 + ou - 1/2 x'= 5+1/2 > 6/2 > 3 x"= 5-1/2 > 4/2 > 2 S={2,3}