Question

equações do primeiro grau a)x+10=3x-10
b)3x=2=4x+9
c)3x-7=2x+5
d)7x+8=4x-10
e)12-2x=2x-12
f)25-4x=7-3x
g)5x-4=8+2x
h)4x-15=-2x+3
i)4-3x=2x+12
​

Answer 1

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Conteúdo ✍ :

➡️ Equação do 1º Grau. ✔️⚽

☔ Para que possamos calcular sua questão, primeiro temos que isolar a incógnita passando os termos com o X para o lado esquerdo da igualdade, invertendo os sinais dos termos nessa passagem.

✈ Por fim, basta dividir o termo do lado direito da igualdade pelo termo do lado esquerdo para descobrirmos o valor de X:

$\large{\boxed{\begin{array}{l} \sf A)\ x + 10=3x-10 \\\\\sf -2x =-10-10\\\\\sf -2x = -20\\\\ \sf x= \dfrac{-20}{-2}\\\\ \sf x= 10 \end{array}}}$ ✅ ✍

$\large{\boxed{\begin{array}{l} \sf B )\ 3x - 2=4x + 9\\\\\sf3x - 4x =9 + 2\\\\\sf -x = 11 \times (-1)\\\\ \sf x= -11 \end{array}}}$  ✅ ✍

$\large{\boxed{\begin{array}{l} \sf C)\ 3x-7=2x+5 \\\\\sf 3x -2x =5+7\\\\\sf x=12 \end{array}}}$  ✅ ✍

$\large{\boxed{\begin{array}{l} \sf D)\ 7x+8=4x-10 \\\\\sf 7x -4x = -10-8\\\\\sf 3x=-18\\\\ \sf x= \dfrac{-18}{3}\\\\ \sf x= -6 \end{array}}}$  ✅ ✍

$\large{\boxed{\begin{array}{l} \sf E)\ 12-2x=2x-12\\\\ \sf -2x -2x = -12 -12\\\\ \sf -4x = -24\\\\ \sf x= \dfrac {-24}{-4}\\\\ \sf x= 6 \end{array}}}$  ✅✍

$\large{\boxed{\begin{array}{l} \sf F)\ 25-4x=7-3x\\\\ \sf -4x +3x=7 -25\\\\ \sf -x = -18 \times (-1)\\\\ \sf x = 18 \end{array}}}$  ✅ ✍

$\large{\boxed{\begin{array}{l} \sf G)\ 5x-4=8+2x\\\\ \sf 5x -2x = 8 +4\\\\ \sf 3x = 12\\\\ \sf x= \dfrac{12}{3}\\\\ \sf x= 4 \end{array}}}$   ✅ ✍

$\large{\boxed{\begin{array}{l} \sf H)\ 4x-15=-2x+3\\\\ \sf 4x +2x = 3 +15\\\\ \sf 6x= 18\\\\ \sf x= \dfrac{18}{6}\\\\ \sf x= 3 \end{array}}}$  ✅ ✍

$\large{\boxed{\begin{array}{l} \sf I)\ 4-3x=2x+12\\\\ \sf -3x -2x = 12 -4\\\\ \sf -5x = 8 \times (-1)\\\\ \sf 5x = -8\\\\ \sf x = - \dfrac{8}{5} \end{array}}}$  ✅ ✍

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