Equações Biquadradas:
Resolva as equações em R:
a)X^4-21X^2+98=0
B)X^4-20X^2+64=0
C)X^4+X^2-110=0
Por favor me ajudem!
Soluções para a tarefa
Respondido por
2
E aí mano,

________________________

________________________

Espero ter ajudado e tenha ótimos estudos =))
________________________
________________________
Espero ter ajudado e tenha ótimos estudos =))
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