Equação: x+7/10=1/2
2) x+4/15=2/3
3)x+4/3=x+3/4
4)4x-7/3=5x/3
5)5x-1/18=11-x/18
6) a)x/6+1/12=1/4
b)x/6-1/3=1/2
c)x+x/3=8
d)x/3-1=x/4
ittalo25:
tá perto roosevelt ? shausua zoeira
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1 ) 
2 )
3 )
4 )
5 )
Essa 5º está alguma coisa errada, não pode se dividir 0, logo é indeterminada..
6 )
a )
b )
c )
d )
I hope you like it.
2 )
3 )
4 )
5 )
Essa 5º está alguma coisa errada, não pode se dividir 0, logo é indeterminada..
6 )
a )
b )
c )
d )
I hope you like it.
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