equaçao log(kx)=2log(x+3)
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log [10] (kx ) = 2 log [10] (x+ 3)
log [10 ] ( kx ) = log [10 ] (x+3)²
kx = (x+3)²
kx = x²+6x + 9
kx = 6x
k = 6
log [10 ] ( kx ) = log [10 ] (x+3)²
kx = (x+3)²
kx = x²+6x + 9
kx = 6x
k = 6
alih7:
valeu!!
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