Equação fracionária do 2 grau
1* 5x X-4 -4
---- - ---- = ----
X-1 X+1 X²-1
2* 1-4X 7-20X 3
----- = ------- + -------
X 1+4X X+4X²
3* 9X X-2 12
---- - ----- = --------
6-X X 6X-X²
Soluções para a tarefa
Respondido por
1
Oi Laine
1•
5x/(x - 1) - (x - 4)/(x + 1) = -4/(x² - 1)
mmc = (x - 1)*(x + 1)
5x*(x + 1) - (x - 1)*(x - 4) = -4
5x² + 5x - x² + 5x - 4 = -4
4x² + 10x = 0
x*(4x + 10) = 0
x1 = 0
x2 = -10/4 = -5/2
2•
(1 - 4x)/x = (7 - 20x)/(1 + 4x) + 3/(x*(1 + 4x))
mmc = x*(1 + 4x)
(1 - 4x)*(1 + 4x) = x*(7 - 20x) + 3
-16x² + 1 = 7x - 20x² + 3
4x² - 7x - 2 = 0
delta
d² = 49 + 32 = 81
d = 9
x1 = (7 + 9)/8 = 16/8 = 2
x2 = (7 - 9)/8 = -2/8 = -1/4
3•
9x/(6 - x) - (x - 2)/x = 12/(x*(6 - x))
mmc = x*(6 - x)
9x² - (x - 2)*(6 - x) = 12
9x² + x² - 8x + 12 = 12
10x² - 8x = 0
5x² - 4x = 0
x*(5x - 4) = 0
x1 = 0
x2 = 4/5
.
1•
5x/(x - 1) - (x - 4)/(x + 1) = -4/(x² - 1)
mmc = (x - 1)*(x + 1)
5x*(x + 1) - (x - 1)*(x - 4) = -4
5x² + 5x - x² + 5x - 4 = -4
4x² + 10x = 0
x*(4x + 10) = 0
x1 = 0
x2 = -10/4 = -5/2
2•
(1 - 4x)/x = (7 - 20x)/(1 + 4x) + 3/(x*(1 + 4x))
mmc = x*(1 + 4x)
(1 - 4x)*(1 + 4x) = x*(7 - 20x) + 3
-16x² + 1 = 7x - 20x² + 3
4x² - 7x - 2 = 0
delta
d² = 49 + 32 = 81
d = 9
x1 = (7 + 9)/8 = 16/8 = 2
x2 = (7 - 9)/8 = -2/8 = -1/4
3•
9x/(6 - x) - (x - 2)/x = 12/(x*(6 - x))
mmc = x*(6 - x)
9x² - (x - 2)*(6 - x) = 12
9x² + x² - 8x + 12 = 12
10x² - 8x = 0
5x² - 4x = 0
x*(5x - 4) = 0
x1 = 0
x2 = 4/5
.
laine232:
Obrigada :)
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