Question

equação exponencial
${4}^{2x - 2} - 17 \times {4}^{x - 2} + 1 = 0$

Answer 1

4^(2x-2)-17. 4^(x-2)+1=0
4^x=u

u²/16-17.u/16+1=0
u²-17u+16/16=0

u²-17u+16=0
u=17+-√225/2
u=17+-15/2
u'=16
u"=1

logo

4^x=16 ou 4^x=1
x=2 ou x=0

$\boxed{\boxed{\boxed{\mathsf{ \textit{x = 0 \: ou \: x = 2}}}}}$
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