equação exponencial
![{3}^{x + 2} + {3}^{x - 2} = 82 {3}^{x + 2} + {3}^{x - 2} = 82](https://tex.z-dn.net/?f=+%7B3%7D%5E%7Bx+%2B+2%7D++%2B++%7B3%7D%5E%7Bx+-+2%7D++%3D+82)
Soluções para a tarefa
Respondido por
3
Vamos aplicar algumas propriedades de logaritmos naturais, acompanhe:
![\displaystyle 3^{x+2} + 3^{x-2}=82 \\ \\ \\\ln 3^{x+2} + \ln 3^{x-2}= \ln 82 \\ \\ \\ (x+2) \cdot \ln 3 + (x-2) \cdot \ln 3 = \ln 82 \\ \\ \\ x \ln 3 + 2 \ln 3 + x \ln 3 - 2 \ln 3 = \ln 82 \\ \\ \\ x \ln 3 + x \ln 3 = \ln 82 \\ \\ \\ 2x \ln 3 = \ln 82 \\ \\ \\ x = \frac{\ln 82}{2 \cdot \ln 3} \\ \\ \\ x = \frac{4,41}{2 \cdot 1,1} \\ \\ \\ x = \frac{4,41}{2,2} \\ \\ \\ \boxed{ x = 2 } \displaystyle 3^{x+2} + 3^{x-2}=82 \\ \\ \\\ln 3^{x+2} + \ln 3^{x-2}= \ln 82 \\ \\ \\ (x+2) \cdot \ln 3 + (x-2) \cdot \ln 3 = \ln 82 \\ \\ \\ x \ln 3 + 2 \ln 3 + x \ln 3 - 2 \ln 3 = \ln 82 \\ \\ \\ x \ln 3 + x \ln 3 = \ln 82 \\ \\ \\ 2x \ln 3 = \ln 82 \\ \\ \\ x = \frac{\ln 82}{2 \cdot \ln 3} \\ \\ \\ x = \frac{4,41}{2 \cdot 1,1} \\ \\ \\ x = \frac{4,41}{2,2} \\ \\ \\ \boxed{ x = 2 }](https://tex.z-dn.net/?f=%5Cdisplaystyle+3%5E%7Bx%2B2%7D+%2B+3%5E%7Bx-2%7D%3D82+%5C%5C+%5C%5C+%5C%5C%5Cln+3%5E%7Bx%2B2%7D+%2B+%5Cln+3%5E%7Bx-2%7D%3D+%5Cln+82+%5C%5C+%5C%5C+%5C%5C+%28x%2B2%29+%5Ccdot+%5Cln+3+%2B+%28x-2%29+%5Ccdot+%5Cln+3+%3D+%5Cln+82+%5C%5C+%5C%5C+%5C%5C+x+%5Cln+3+%2B+2+%5Cln+3+%2B+x+%5Cln+3+-+2+%5Cln+3+%3D+%5Cln+82+%5C%5C+%5C%5C+%5C%5C+x+%5Cln+3+%2B+x+%5Cln+3+%3D+%5Cln+82+%5C%5C+%5C%5C+%5C%5C+2x+%5Cln+3+%3D+%5Cln+82+%5C%5C+%5C%5C+%5C%5C+x+%3D+%5Cfrac%7B%5Cln+82%7D%7B2+%5Ccdot+%5Cln+3%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D+%5Cfrac%7B4%2C41%7D%7B2+%5Ccdot+1%2C1%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D+%5Cfrac%7B4%2C41%7D%7B2%2C2%7D+%5C%5C+%5C%5C+%5C%5C+%5Cboxed%7B+x+%3D+2+%7D)
jvma1:
então cara, é que tá meio diferente do que estou aprendendo
Perguntas interessantes
Matemática,
11 meses atrás
Matemática,
11 meses atrás
Geografia,
11 meses atrás
Matemática,
1 ano atrás
Português,
1 ano atrás