Question

Equação exponencial, me ajudem 0,25^2x+3 = 4^x-1

Answer 1

$0,25^{2x + 3}= 4^{x-1} \\ \\ ( \frac{1}{4}) ^{2x+3}=4^{x-1} \\ \\ (4^{-1})^{2x+3}=4^{x-1} \\ \\ 4^{-2x-3}=4^{x-1} \\ \\ -2x-3 = x -1 \\ \\ -2x - x = -1 + 3 \\ \\ -3x = 2 \\ \\ x = - \frac{2}{3}$

Espero ter ajudado.

Answer 2

Temos que:

$(0,25)^{2x + 3} = 4^{x-1} \\ \\ ( \frac{1}{4} )^{2x+3} = 4^{x-1} \\ \\ 4^{-1*(2x+3)} = 4^{x-1} \\ \\ 4^{-2x - 3} = 4^{x-1}$

Igualando:

$-2x - 3 = x - 1 \\ \\ -3x = 2 \\ \\ x = - \frac{2}{3}$